Your Name: _______________________ PHY203
Final
Exam
Student ID: ________________________ Chapters
1-12,14
12/12/02
, 3-6 p.m.
Lecture Time: 9
a.m 1p.m. 2p.m. 3p.m. Honors
1 _________________ 7 __________________
2 _________________ 8 __________________
Part
1 ____________ 9 __________________
Part
4 __________
3 _________________
4 _________________
Total
_______________
Part
2 ____________
5 _________________
6 _________________
Part
3 ____________
3.
Two blocks, (m1 =10 kg and m2
=20kg) are positioned as shown below.
The first mass rests on a frictionless surface the second mass is
suspended by a string. Assume the pulley is massless.

a.
Redraw the blocks below and sketch all of the forces on each block (free
body diagrams).
b.
Write Newton’s force equation in both axes for both masses.
c.
Calculate the magnitude of the acceleration, a, of the blocks and the
magnitude of the tension in the string,T.
4. A
mass of m=5 kg is attached to a string with a length of 0.5 m. The mass is then
released from a horizontal position at point A, with speed vo=5 m/s, as shown below. It swings through vertical point B and eventually encounters
a spring. The spring is compressed
by 5 cm until the ball comes to rest at the horizontal position at point C.

a. Using
conservation of energy, calculate the velocity of the mass at point B.
b. Calculate
the tension, T, in the string at point B.
c. Calculate
the spring constant, k, of the spring.
PHY203
Exam
#2, F/02
Crib
Sheet
(Note: Use 9.81 m/s2 for g, the acceleration due to gravity.)
For constant acceleration(in one
dimension):
xf = xo
+ vot + (1/2)at2
vf = vo
+ at
vf2 =
vo2 + 2a(xf - xo)
(Note: Bold letters indicate vectors below.)
F
= ma
spring force: F = -kDx ,
where k is the spring constant
weight: W = mg
friction force:
kinetic fk = mkFn ,
where Fn is the normal force and mk is the
kinetic frictional coefficient
static fs < msFn,
fsmax = msFn
uniform circular motion
centripetal acceleration: a = v2/R
W = F
. d = Fdcosq
Work done by friction = -fkDs
EThermal =
|Work done by friction|
Kinetic Energy: K = (1/2)mv2
Potential Energy: Uspring = (1/2)kx2
Ugrav
= mgh
Total energy, E, is conserved ( a constant).