Your Name: _______________________ PHY203

Final Exam

Student ID: ________________________ Chapters 1-12,14

12/17/04

11:30-2:30 p.m.

Lecture Time: 9 a.m 1p.m. 2p.m. 3p.m. Honors

1 _________________ 7 __________________

2 _________________ 8 __________________

Part 1 (out of 100)____________ Part 4 (out of 100)____________

3 _________________

4 _________________

Total (out of 400)_______________

Part 2 (out of 100)____________

5 _________________

6 _________________

Part 3 (out of 100)____________
Your Name: _______________________

1.

For the graphs above, indicate the graphs which meet the following conditions:

a. acceleration is constant

b. acceleration is not constant

c. velocity is constant

d. velocity reverses its direction

e. Which graphs of position, velocity, and acceleration are mutually consistent?

Your Name: _______________________

2. A missile is shot in a horizontal direction from a cliff with height 20m and initial speed of 100m/s, as shown. (Note: Use 9.81 m/s2 for the magnitude of g.)

a. Write the initial velocity vector, v_o, in vector notation.

b. Calculate the time in sec. that it will take for the missile to hit the ground.

c. Calculate the x position at which the missile will hit the ground.

d. Calculate the final velocity, v_f, of the missile just before it hits the ground (and present it in vector form).

e. Calculate the final speed of the missile just before it hits the ground.

PHY203

Crib Sheet

Chapters 1-3

1D case:

speed_AV = (total distance traveled)/Dt

v_AV = Dx/Dt

a_AV = Dv/Dt

v_Inst = dx/dt

a_Inst = dv/dt

For constant acceleration:

x_f = x_o + v_ot + (1/2)at2

v_f = v_o + at

V_f2 = v_o2 + 2a(x_f - x_o)

(Note: Use 9.81 m/s2 for g, the acceleration due to gravity.)

For a vector A with magnitude A and direction q (measured counterclockwise with respect to the x-axis):

A_x = Acos(q)

A_y = Asin(q)

A = (A_x² + A_y²)^1/2

tan(q) = A_y/A_x

quadratic eq. sol.: If ax² + bx + c = 0; then x = -b+(b²-4ac)^1/2/(2a)

PHY203

Crib Sheet

Chapters 4-7

(Note: Use 9.81 m/s2 for g, the acceleration due to gravity.)

For constant acceleration(in one dimension):

x_f = x_o + v_ot + (1/2)at2

v_f = v_o + at

v_f2 = v_o2 + 2a(x_f - x_o)

(Note: Bold letters indicate vectors below.)

F = ma

spring force: F = -kDx , where k is the spring constant

weight: W = mg

friction force:

kinetic fk = mkFn , where Fn is the normal force and mk is the kinetic frictional coefficient

static fs < msFn, fsmax = msFn

uniform circular motion

centripetal acceleration: a = v2/R

Work and Energy

W = F ^. d = Fdcosq

Work done by friction = -f_kDs

E_Thermal = |Work done by friction|

Kinetic Energy: K = (1/2)mv²

Potential Energy: U_spring = (1/2)kx²

U_grav = mgh

Total energy, E, is conserved ( a constant).